In an ap a 1 an 20 sn 399

WebWe can conclude that 10, 20, 30…, 500 is an AP with common difference, d = 10. First term, a = 10. Let the number of terms in this AP = n. Using nth term formula, an = a + (n – 1)d. 500 = 10 + (n – 1)10. 490 = (n – 1)10. n – 1 = 49. n = 50. Sum of an AP, Sn = (n/2) [ a + an], here an is the last term, which is given] = (50/2) ×[10 ... WebIn an AP, if a = 1, an = 20 and Sn = 399, then n is equal to (a) 19 (b) 21 (c) 38 (d) 42 Solution: Question 18: The sum of first five multiples of 3 is (a) 45 (b) 55 (c) 65 (d) 75 Solution: (a) The first five multiples of 3 are 3, 6, 9,12 and 15. Here, first term, a = 3, common difference, d = 6-3 = 3 and number of terms, n = 5

In an AP if a = 1, aₙ = 20 and Sₙ = 399, then n is

WebHere d = 19 – 20 = (–1) and S n = 200 Hence, the required number of rows are 16 and in the top row there are 5 logs. 224 Views. Answer . The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. Let the first term and the common difference of the A .P. be a and d ... WebOct 25, 2015 · In an AP, if a=1,an=20 and Sn= 399, then n=? Advertisement Expert-Verified Answer 603 people found it helpful Brainly User since , an = a+ (n-1)d 20 = 1 + (n-1)d 19 = … phil heasley butler pa https://state48photocinema.com

In an A.P. , if a = 1, an= 20 and sn =399, then n is? - Meritnation

WebIn an AP if a=1, an =20 and Sn =399, then n is Q. If an AP has a=1, tn=20 and Sn=399, then the value of n is Q. In an AP, if d = - 4 , n = 7 and an = 4, then a is equal to A) 6 B) 7 C) 20 D) … WebQuestion If an AP has a = 1, a n = 20 and S n = 399, then find the value of n. Solution Compute the value of n: Formulae: The n th term of an AP is a n = a + n - 1 d and the sum of n terms of a series in an AP is S n = n 2 2 a + ( n - 1) d. Substitute a = 1, a n = 20 in the n th term of an AP formula. WebÿØÿî AdobedÀ ÿÛ„ ÿÀ € ÿÄØ ! phil heart center training

In an AP, if a=1,an=20 and Sn= 399, then n=? - Brainly

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In an ap a 1 an 20 sn 399

In an AP if a=1, a_n=20 and S_n=399, then n is (A) 19 (B) 21 (C) 38 ...

WebIf an A.P. has a = 1, t n = 20 and s n = 399, then value of n is : A. 20 B. 32 C. 38 D. 40 Answer: Option C Solution (By Examveda Team) S n = 1 2 ( a + l) × n ⇒ 399 = ( 1 + 20) × n 2 ⇒ 399 × 2 = 21 × n ⇒ n = 399 × 2 21 ⇒ n = 19 × 2 ⇒ n = 38 Join The Discussion Related Questions on Progressions How many terms are there in 20, 25, 30 . . . . . . 140?

In an ap a 1 an 20 sn 399

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WebAug 25, 2024 · In an AP, if a = 1, an = 20 and Sn = 399, then n is equal to A. 19 B. 21 C. 38 D. 42. ← Prev Question Next Question →. 0 votes. 17.2k views. asked Aug 25, 2024 in … WebFeb 26, 2016 · WE HAVE- SN=399 , A=1 & AN=20. {Sn=n/2 (a+an)} =>so lets substitute... 399=n/2 (a+an) 399=n/2 (1+20) 399=n/2 (21) =>lets send 2 and 21 to RHS. 399X2/21=n. …

WebFeb 14, 2024 · Solution For (2) In an AP if a=1,an =20, and Sn =399,0 then n is equal a=1an =20Sn =399 WebMar 11, 2024 · answered In an Ap, a=1, an=20, sn=399 then find n Advertisement Answer 3 people found it helpful pragyanrana31 Answer: Sn=n/2 (a+l) . . 399=n/2 (1+20) . . 399*2/21=n . . 19*2=n . . N=38 . . Hope this helps you . . Pls mark Brainliest answer! ️ Find Math textbook solutions? Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 …

WebSolution: An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term. The nth term of an AP is. aₙ = a + (n - 1 )d. a = first term. aₙ = nth term. d = common difference. Considering the question, we get the value as, WebIn an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42 Home Get Answers to all your Questions Home NCERT In an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42 #Arithmetic Progressions #NCERT #Maths #Exemplar Maths for Class 10 #1.3 #5.2 #5.3 #5.4 #5.1 #9.2 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0

WebMar 19, 2024 · In an AP, if a = 1, an = 20 and Sn = 399, then n is equal to A. 19 B. 21 C. 38 D. 42. asked Aug 25, 2024 in Arithmetic Progression by Sima02 (49.6k points) arithmetic progression; class-10; Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries.

WebFeb 27, 2012 · In an AP if a=1, an= 20 and sn =399 then n is a) 13 b) 38 c) 21 d)19 - Maths - Arithmetic Progressions phil heaterWebIn an A.P 1 st term is 1 and the last term is 20. The sum of all terms is =399 then n= .... A 42 B 38 C 21 D 19 Medium Solution Verified by Toppr Correct option is B) The is given that, First term (a)=1 Last term (t n)=20 Sum of terms (S n)=399 We know that, t n=a+(n−1)d S n= 2n(2a+(n−1)d) S n= 2n(a+(a+(n−1)d)) ⇒S n= 2n(a+t n) ⇒399= 2n(1+20) phil-heath-2008Web98 Likes, 0 Comments - АВТОМОБИЛЬ•ВЫКУП•ОБМЕН•ПРОДАЖА (@avtomarket04) on Instagram: "⚡️Datsun Mi-Do⚡️ Год выпуска ... phil heath 2015 trainingWebBesides giving the explanation of In an A.P. if a=1,An=20 and Sn=399, then find the value of n.?, a detailed solution for In an A.P. if a=1,An=20 and Sn=399, then find the value of n.? … phil heath 2002WebFeb 11, 2013 · if an ap a=1 ,an=20,sn= 399 then n is Asked by anish mishra 11 Feb, 2013, 02:45: PM Expert Answer Sn=399 => n/2 (a + an) = 399 => n/2 ( 1 + 20) = 399 =>n/2 (21) = 399 => n = 399 X 2/21 => n= 38 Answered by 11 Feb, 2013, 05:49: PM Application Videos This video explains the concept of Arithmetic Progression, Solving Linear E... phil heath 2010WebFeb 22, 2013 · In an A.P. , if a = 1, an= 20 and sn =399, then n is? Share with your friends 1 Follow 0 Jai Prakash, added an answer, on 22/2/13 we know from that formula that, Sn = n/2 (a + an) 399 = n/2 (1 + 20) 399*2 = n (21) n = 798/21 = 38 Therefore n = 38 Was this answer helpful? 3 View Full Answer phil heath 2012WebAn arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous … phil heath 180 to 280