Highest power of 2 in 1000
WebCorrect option is D) We have to find the the largest n such that 1000! is divided by 13 n. This equivalent to find the largest power 13 present in 1000!=1⋅2⋅ 3⋯13⋯26⋯169⋯1000 … WebWe could also compute the number of factors of $2$ that divide $50!$: $50=110010_\text{two}$ so $\sigma_2(50)=3$ and the number of factors of $2$ that divide $50!$ is $$ \frac{50-3}{2-1}=47 $$ Thus, there are enough factors of $2$ to match the number of factors of $5$. This ensures that the number of factors of $10$ in $50!$ is $12$.
Highest power of 2 in 1000
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Web6 de jan. de 2024 · Dr.Momin Awan is a Leading Energy Consultant Having PhD in Electrical Engineering From Bradford University Uk. Over all … Web14 de out. de 2016 · The formula for the exponent of the highest power of prime p dividing n! is ∑ n p k, but the question is n = 1000! (really, it has the factorial) and p = 5. When I use Wolfram Alpha , I panicked because the number has 2, 567 decimal digits. I think if I write this number I'd need paper all the way to the Amazon. Perhaps I misunderstand the …
WebAssume n! and its prime factors 2,3,5,7… n! = 2e1.3e2.5e3… e1 is the highest power of the prime number 2, e2 is the highest power of the prime number 3, and so on… For n …
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